Skip to main content

Solving Simultaneous Equation By Elimination Method

Solving Simultaneous Equation By Elimination 

Method

3x+2y=6

 5y= 8

In order to solve by elimination, coefficients of one of the variables must be the same in both equations so that the variable will cancel out when one equation is subtracted from the other

3x+2y=65xy=8


5×3x+5×2y=5×6,3×5x+3(1)y=3×8

Simplify

15x+10y=30,15x3y=24

Subtract 15x3y=24 from  by subtracting like terms on each side of the equal sign

15x15x+10y+3y=3024

Cancel out 15x - 15x to get 

10y+3y=3024

Add  to  

13y=3024

Subtract 24 from 30 to get

13y= 6

Divide both side by 13

y=136

5x136=8

5x=13110

Divide through by 5

x=1322

x=1322,y=136

Comments

Popular posts from this blog

How to find the vertical angle of the cone.

 A cone of height 9cm has a volume of ncm cube and a curved surface area of of ncm square. Find the vertical angle of the cone.   SOLUTION

How to calculate the volume of a regular hexagonal nut

 How to calculate the volume of a regular hexagonal nut Calculate the volume of a regular hexagonal nut of side 1cm and length 3cm with a central hole of diameter 1cm. Ignore the thread and give your answer to 3 significant figures. Solution To solve any problem in mathematics you have to read and understand the problem you are to solve, especially word problem related questions. Failure to carefully read the question might lead to wrong interpretation of the problem and the result of it will be wrong solution to the problem. All problems on this platform have been carefully solved and prepared. If you are a student looking for solutions to your assignments then you are at the right place.  If you are an upcoming teacher looking for solution to a challenging question then you are also at the right place.  You can as well contribute to the growth of this platform by sending questions and answers using the  comment box . Ensure that questions and answers sent are corre...

How to find the common difference of AP when the first and last term are given

 How to find the common difference of AP when the first and last term are given Question: The first and last terms of an AP are 6.7  and 17.1 respectively. If there are 14 terms in the sequence, find its common difference.  Solution First term of the sequence a = 6.7 Last term of the sequence Tn = 17.1 Since the sequence has 14 terms, it means that the 14th term is the last term Therefore:  Tn = T14 = 17.1  Recall the nth term formula Tn = a + (n-1)d Substitute Tn for T14, a for 6.7 and n for 14 to get the formula below T14 = 6.7 + (14-1)d T14 = 6.7 + 13d Substitute T14 for 17.1 T14 = 6.7 + 13d 17.1 = 6.7 + 13d Subtract 6.7 from both sides to get 17.1 - 6.7 = 6.7-6.7 +13d 10.4 = 13d Divide through by 13 10.4/13 = 13d/13 d = 104/130 The common difference is 104/130 CHECK Substitute 104/130 for d in T14 = 6.7 + 13d  T14 = 6.7 + 13*104/130        = (6.7*130 + 13*104)/130        = (871 + 1352)/130       ...