Question Find the number of terms in an Ap given that its first and last terms are a and 37a respectively and that its common difference is 4a. Solution nth term of AP Tn = a +(n-1)d From the question First term a = a Last term Tn = 37a Common difference d = 4a Number of terms n =? Substitute a, Tn and d into the nth term formula Tn = a +(n-1)d 37a = a +(n-1)4a Collect like terms 37a-a = (n-1)4a 36a = (n-1)4a Divide through by 4a 36a/4a = (n-1)4a/4a 9 = n-1 make n subject formula n = 9+1 n = 10 The AP as 10 terms
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