Skip to main content

How to plot One linear, one quadratic graph.

How to plot One linear, one quadratic graph


Question:
(a) Draw the graph of  https://tellmath.blogspot.com/2021/01/logarithm.htmlfor values of x from -4 to 2

(b) Use the graph to solve the equations
https://tellmath.blogspot.com/2021/01/logarithm.html
                   
  ( c) By drawing the line  y = 2x + 1 on the same axes, solve the equation       
https://tellmath.blogspot.com/2021/01/logarithm.html

         
     

Solution

First find the values of y for every value of x. I will only calculate for few values of x to get their corresponding values of y. This part is very important and care need to be taken because any wrong value got will render all your effort useless. The calculation is simple substitution of the given values of x to the equation.  Just that, see below
https://tellmath.blogspot.com/2021/01/logarithm.html

 Below is the table of the calculation 
https://tellmath.blogspot.com/2021/01/logarithm.html
Calculate also for the line graph to get the table below. Same method of substitution.
https://tellmath.blogspot.com/2021/01/logarithm.html
Plot the graph as shown below
https://tellmath.blogspot.com/2021/01/logarithm.html

Follow the steps below the needed values from the graph

https://tellmath.blogspot.com/2021/01/logarithm.html

















 

Comments

Popular posts from this blog

How to find the vertical angle of the cone.

 A cone of height 9cm has a volume of ncm cube and a curved surface area of of ncm square. Find the vertical angle of the cone.   SOLUTION

Solving Simultaneous equation using matrix method

Solving Simultaneous equation  using matrix  Method Question: Find the values of  x and y in the equations below 3 x + 2 y = 6 5 x − y = 8 Using matrix method Put the equations in standard form and then use matrices to solve the system of equations. 3 x + 2 y = 6 , 5 x − y = 8 Write the equations in matrix form ( 3 5 ​ 2 − 1 ​ ) ( x y ​ ) = ( 6 8 ​ ) Left multiply the equation by the inverse matrix of  ( 3 5 ​ 2 − 1 ​ ) . i n v e r s e ( ( 3 5 ​ 2 − 1 ​ ) ) ( 3 5 ​ 2 − 1 ​ ) ( x y ​ ) = i n v e r s e ( ( 3 5 ​ 2 − 1 ​ ) ) ( 6 8 ​ ) The product of a matrix and its inverse is the identity matrix ( 1 0 ​ 0 1 ​ ) ( x y ​ ) = i n v e r s e ( ( 3 5 ​ 2 − 1 ​ ) ) ( 6 8 ​ ) Multiply the matrices on the left hand side of the equal sign. ( x y ​ ) = i n v e r s e ( ( 3 5 ​ 2 − 1 ​ ) ) ( 6 8 ​ ) For the  2 × 2  matrix  ( a c ​ b d ​ ) , the inverse matrix is  ( a d − b c d ​ a d − b c − c ​ ​ a d − b c − b ​ a d − b c a ​ ​ ) , so the matrix equation can be ...

Arithmetic Progression

How to calculate the common difference when the first term and the nth term is know.  Question: The 28th term of an AP is -5. Find the common difference if its first term is 31. Solution T1 = a ( First term of the sequence) a = 31 T28 = -5 (28th term of the sequence) d = ? (common difference) Recall the nth term formula of Ap i.e  Tn = a + (n-1)d        Substitute 28 for n to get the following equation        T28 = a + (28-1)d          T28     = a + 27d        Substitute T28 for -5 and 31 for a  in the equation above               -5     = 31 + 27d          Subtract 31 from both sides of the equation         -5 -31 = 27d          -36 = 27d        Divide through by 27        -36/27  =  27d/27 ...